Base | Representation |
---|---|
bin | 10100111000101100… |
… | …10000000001111001 |
3 | 1001221110021002021222 |
4 | 22130112100001321 |
5 | 140431012404423 |
6 | 5052353441425 |
7 | 544604016221 |
oct | 123426200171 |
9 | 31843232258 |
10 | 11213013113 |
11 | 48344a9795 |
12 | 220b270275 |
13 | 10990b9b03 |
14 | 7852bd081 |
15 | 4596193c8 |
hex | 29c590079 |
11213013113 has 2 divisors, whose sum is σ = 11213013114. Its totient is φ = 11213013112.
The previous prime is 11213013089. The next prime is 11213013137. The reversal of 11213013113 is 31131031211.
It is a balanced prime because it is at equal distance from previous prime (11213013089) and next prime (11213013137).
It can be written as a sum of positive squares in only one way, i.e., 5667530089 + 5545483024 = 75283^2 + 74468^2 .
It is a cyclic number.
It is not a de Polignac number, because 11213013113 - 222 = 11208818809 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11213013091 and 11213013100.
It is not a weakly prime, because it can be changed into another prime (11213013143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606506556 + 5606506557.
It is an arithmetic number, because the mean of its divisors is an integer number (5606506557).
Almost surely, 211213013113 is an apocalyptic number.
It is an amenable number.
11213013113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213013113 is an equidigital number, since it uses as much as digits as its factorization.
11213013113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11213013113 its reverse (31131031211), we get a palindrome (42344044324).
The spelling of 11213013113 in words is "eleven billion, two hundred thirteen million, thirteen thousand, one hundred thirteen".
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