Base | Representation |
---|---|
bin | 11001011111101110001111… |
… | …101001001011011001001101 |
3 | 112201000122000121221100020100 |
4 | 121133232033221023121031 |
5 | 104144124014002230013 |
6 | 1034252154221441313 |
7 | 32422130466333654 |
oct | 3137561751133115 |
9 | 481018017840210 |
10 | 112131121133133 |
11 | 328015a569a013 |
12 | 106ab919710239 |
13 | 4a74bc4a7a12b |
14 | 1d99264b3a19b |
15 | ce6bc3bb1473 |
hex | 65fb8fa4b64d |
112131121133133 has 12 divisors (see below), whose sum is σ = 171494655850908. Its totient is φ = 70356781887360.
The previous prime is 112131121133117. The next prime is 112131121133137. The reversal of 112131121133133 is 331331121131211.
112131121133133 is a `hidden beast` number, since 1 + 1 + 2 + 1 + 311 + 2 + 11 + 331 + 3 + 3 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 49351439903364 + 62779681229769 = 7025058^2 + 7923363^2 .
It is not a de Polignac number, because 112131121133133 - 24 = 112131121133117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112131121133097 and 112131121133106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112131121133137) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 366441572178 + ... + 366441572483.
It is an arithmetic number, because the mean of its divisors is an integer number (14291221320909).
Almost surely, 2112131121133133 is an apocalyptic number.
It is an amenable number.
112131121133133 is a deficient number, since it is larger than the sum of its proper divisors (59363534717775).
112131121133133 is a wasteful number, since it uses less digits than its factorization.
112131121133133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 732883144684 (or 732883144681 counting only the distinct ones).
The product of its digits is 972, while the sum is 27.
Adding to 112131121133133 its reverse (331331121131211), we get a palindrome (443462242264344).
The spelling of 112131121133133 in words is "one hundred twelve trillion, one hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-three thousand, one hundred thirty-three".
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