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11213141 is a prime number
BaseRepresentation
bin101010110001…
…100101010101
3210002200112112
4222301211111
510332310031
61040200405
7164211242
oct52614525
923080475
1011213141
116369665
123909105
132427ac4
1416bc5c9
15eb762b
hexab1955

11213141 has 2 divisors, whose sum is σ = 11213142. Its totient is φ = 11213140.

The previous prime is 11213129. The next prime is 11213143. The reversal of 11213141 is 14131211.

11213141 is digitally balanced in base 2 and base 3, because in such bases it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10048900 + 1164241 = 3170^2 + 1079^2 .

It is a cyclic number.

It is not a de Polignac number, because 11213141 - 26 = 11213077 is a prime.

Together with 11213143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606570 + 5606571.

It is an arithmetic number, because the mean of its divisors is an integer number (5606571).

Almost surely, 211213141 is an apocalyptic number.

It is an amenable number.

11213141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213141 is an equidigital number, since it uses as much as digits as its factorization.

11213141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 24, while the sum is 14.

The square root of 11213141 is about 3348.6028429779. The cubic root of 11213141 is about 223.8252583310.

Adding to 11213141 its reverse (14131211), we get a palindrome (25344352).

The spelling of 11213141 in words is "eleven million, two hundred thirteen thousand, one hundred forty-one".