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11213213001103 is a prime number
BaseRepresentation
bin1010001100101100011110…
…0100111110010110001111
31110200222021002112100212001
42203023013210332112033
52432204130012013403
635503140130053131
72235061604611411
oct243130744762617
943628232470761
1011213213001103
113633551458433
12131124241a1a7
1363452aca1a79
142aaa183ca9b1
15146a34b06c1d
hexa32c793e58f

11213213001103 has 2 divisors, whose sum is σ = 11213213001104. Its totient is φ = 11213213001102.

The previous prime is 11213213001101. The next prime is 11213213001119. The reversal of 11213213001103 is 30110031231211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11213213001103 - 21 = 11213213001101 is a prime.

It is a super-2 number, since 2×112132130011032 (a number of 27 digits) contains 22 as substring.

Together with 11213213001101, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213213001101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606606500551 + 5606606500552.

It is an arithmetic number, because the mean of its divisors is an integer number (5606606500552).

Almost surely, 211213213001103 is an apocalyptic number.

11213213001103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213213001103 is an equidigital number, since it uses as much as digits as its factorization.

11213213001103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 11213213001103 its reverse (30110031231211), we get a palindrome (41323244232314).

The spelling of 11213213001103 in words is "eleven trillion, two hundred thirteen billion, two hundred thirteen million, one thousand, one hundred three".