Base | Representation |
---|---|
bin | 10000010100010100000… |
… | …011111100101001111111 |
3 | 10222012022221010121101221 |
4 | 100110110003330221333 |
5 | 121332432144342310 |
6 | 2215043444214211 |
7 | 144004300414666 |
oct | 20242403745177 |
9 | 3865287117357 |
10 | 1121323043455 |
11 | 3a260669715a |
12 | 1613a099a367 |
13 | 819815c8654 |
14 | 3c3b538bddd |
15 | 1e27c95eada |
hex | 105140fca7f |
1121323043455 has 8 divisors (see below), whose sum is σ = 1345594118112. Its totient is φ = 897054124128.
The previous prime is 1121323043431. The next prime is 1121323043473. The reversal of 1121323043455 is 5543403231211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121323043455 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1121323043455.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1010977 + ... + 1806853.
It is an arithmetic number, because the mean of its divisors is an integer number (168199264764).
Almost surely, 21121323043455 is an apocalyptic number.
1121323043455 is a deficient number, since it is larger than the sum of its proper divisors (224271074657).
1121323043455 is an equidigital number, since it uses as much as digits as its factorization.
1121323043455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1077665.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 1121323043455 its reverse (5543403231211), we get a palindrome (6664726274666).
The spelling of 1121323043455 in words is "one trillion, one hundred twenty-one billion, three hundred twenty-three million, forty-three thousand, four hundred fifty-five".
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