11213401201133 has 2 divisors, whose sum is σ = 11213401201134. Its totient is φ = 11213401201132.

The previous prime is 11213401201097. The next prime is 11213401201151. The reversal of 11213401201133 is 33110210431211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10753821607204 + 459579593929 = 3279302^2 + 677923^2 .

It is an emirp because it is prime and its reverse (33110210431211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11213401201133 - 2¹⁰ = 11213401200109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11213401201099 and 11213401201108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213401201333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606700600566 + 5606700600567.

It is an arithmetic number, because the mean of its divisors is an integer number (5606700600567).

Almost surely, 2^{11213401201133} is an apocalyptic number.

It is an amenable number.

11213401201133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213401201133 is an equidigital number, since it uses as much as digits as its factorization.

11213401201133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11213401201133 its reverse (33110210431211), we get a palindrome (44323611632344).

The spelling of 11213401201133 in words is "eleven trillion, two hundred thirteen billion, four hundred one million, two hundred one thousand, one hundred thirty-three".