112134331213241 has 2 divisors, whose sum is σ = 112134331213242. Its totient is φ = 112134331213240.

The previous prime is 112134331213231. The next prime is 112134331213243. The reversal of 112134331213241 is 142312133431211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111884035125625 + 250296087616 = 10577525^2 + 500296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112134331213241 is a prime.

It is a Sophie Germain prime.

Together with 112134331213243, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 112134331213198 and 112134331213207.

It is not a weakly prime, because it can be changed into another prime (112134331213243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56067165606620 + 56067165606621.

It is an arithmetic number, because the mean of its divisors is an integer number (56067165606621).

Almost surely, 2^{112134331213241} is an apocalyptic number.

It is an amenable number.

112134331213241 is a deficient number, since it is larger than the sum of its proper divisors (1).

112134331213241 is an equidigital number, since it uses as much as digits as its factorization.

112134331213241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10368, while the sum is 32.

Adding to 112134331213241 its reverse (142312133431211), we get a palindrome (254446464644452).

The spelling of 112134331213241 in words is "one hundred twelve trillion, one hundred thirty-four billion, three hundred thirty-one million, two hundred thirteen thousand, two hundred forty-one".