1121401313 has 4 divisors (see below), whose sum is σ = 1121496468. Its totient is φ = 1121306160.

The previous prime is 1121401289. The next prime is 1121401327. The reversal of 1121401313 is 3131041211.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3131041211 = 13763 ⋅227497.

It can be written as a sum of positive squares in 2 ways, for example, as 855972049 + 265429264 = 29257^2 + 16292^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121401313 - 2³⁰ = 47659489 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1121401291 and 1121401300.

It is not an unprimeable number, because it can be changed into a prime (1121401213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26906 + ... + 54467.

It is an arithmetic number, because the mean of its divisors is an integer number (280374117).

Almost surely, 2^1121401313 is an apocalyptic number.

It is an amenable number.

1121401313 is a deficient number, since it is larger than the sum of its proper divisors (95155).

1121401313 is an equidigital number, since it uses as much as digits as its factorization.

1121401313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95154.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1121401313 is about 33487.3306341368. The cubic root of 1121401313 is about 1038.9317535224.

Adding to 1121401313 its reverse (3131041211), we get a palindrome (4252442524).

The spelling of 1121401313 in words is "one billion, one hundred twenty-one million, four hundred one thousand, three hundred thirteen".