Base | Representation |
---|---|
bin | 10000010100011000110… |
… | …001100001110101101111 |
3 | 10222012112102220011002222 |
4 | 100110120301201311233 |
5 | 121333112414213403 |
6 | 2215055350505555 |
7 | 144006250404524 |
oct | 20243061416557 |
9 | 3865472804088 |
10 | 1121402101103 |
11 | 3a2647284359 |
12 | 1614033652bb |
13 | 81994ab8b1b |
14 | 3c3c1a8b14b |
15 | 1e284879338 |
hex | 10518c61d6f |
1121402101103 has 2 divisors, whose sum is σ = 1121402101104. Its totient is φ = 1121402101102.
The previous prime is 1121402101097. The next prime is 1121402101121. The reversal of 1121402101103 is 3011012041211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121402101103 - 212 = 1121402097007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121402101003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560701050551 + 560701050552.
It is an arithmetic number, because the mean of its divisors is an integer number (560701050552).
Almost surely, 21121402101103 is an apocalyptic number.
1121402101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121402101103 is an equidigital number, since it uses as much as digits as its factorization.
1121402101103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 1121402101103 its reverse (3011012041211), we get a palindrome (4132414142314).
The spelling of 1121402101103 in words is "one trillion, one hundred twenty-one billion, four hundred two million, one hundred one thousand, one hundred three".
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