Base | Representation |
---|---|
bin | 10100111000110101… |
… | …11011111011001011 |
3 | 1001221112120111022011 |
4 | 22130122323323023 |
5 | 140431321211413 |
6 | 5052440040351 |
7 | 544620323404 |
oct | 123432737313 |
9 | 31845514264 |
10 | 11214241483 |
11 | 4835168675 |
12 | 220b7630b7 |
13 | 1099429c63 |
14 | 78551c9ab |
15 | 4597ad33d |
hex | 29c6bbecb |
11214241483 has 2 divisors, whose sum is σ = 11214241484. Its totient is φ = 11214241482.
The previous prime is 11214241481. The next prime is 11214241487. The reversal of 11214241483 is 38414241211.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11214241483 - 21 = 11214241481 is a prime.
Together with 11214241481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11214241481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607120741 + 5607120742.
It is an arithmetic number, because the mean of its divisors is an integer number (5607120742).
Almost surely, 211214241483 is an apocalyptic number.
11214241483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11214241483 is an equidigital number, since it uses as much as digits as its factorization.
11214241483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6144, while the sum is 31.
Adding to 11214241483 its reverse (38414241211), we get a palindrome (49628482694).
The spelling of 11214241483 in words is "eleven billion, two hundred fourteen million, two hundred forty-one thousand, four hundred eighty-three".
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