11214321340333 has 2 divisors, whose sum is σ = 11214321340334. Its totient is φ = 11214321340332.

The previous prime is 11214321340303. The next prime is 11214321340357. The reversal of 11214321340333 is 33304312341211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10990935606564 + 223385733769 = 3315258^2 + 472637^2 .

It is an emirp because it is prime and its reverse (33304312341211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11214321340333 - 2⁵ = 11214321340301 is a prime.

It is a super-2 number, since 2×11214321340333² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11214321340295 and 11214321340304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11214321340303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607160670166 + 5607160670167.

It is an arithmetic number, because the mean of its divisors is an integer number (5607160670167).

Almost surely, 2^{11214321340333} is an apocalyptic number.

It is an amenable number.

11214321340333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11214321340333 is an equidigital number, since it uses as much as digits as its factorization.

11214321340333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 11214321340333 its reverse (33304312341211), we get a palindrome (44518633681544).

The spelling of 11214321340333 in words is "eleven trillion, two hundred fourteen billion, three hundred twenty-one million, three hundred forty thousand, three hundred thirty-three".