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11214433130 = 251121443313
BaseRepresentation
bin10100111000110111…
…01010101101101010
31001221112221020012012
422130123222231222
5140431343330010
65052444115522
7544622052215
oct123433525552
931845836165
1011214433130
11483528965a
12220b835ba2
131099496264
1478556c77c
154597ea005
hex29c6eab6a

11214433130 has 8 divisors (see below), whose sum is σ = 20185979652. Its totient is φ = 4485773248.

The previous prime is 11214433057. The next prime is 11214433141. The reversal of 11214433130 is 3133441211.

It can be written as a sum of positive squares in 2 ways, for example, as 11206974769 + 7458361 = 105863^2 + 2731^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11214433096 and 11214433105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 560721647 + ... + 560721666.

Almost surely, 211214433130 is an apocalyptic number.

11214433130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11214433130 is a deficient number, since it is larger than the sum of its proper divisors (8971546522).

11214433130 is a wasteful number, since it uses less digits than its factorization.

11214433130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1121443320.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11214433130 its reverse (3133441211), we get a palindrome (14347874341).

The spelling of 11214433130 in words is "eleven billion, two hundred fourteen million, four hundred thirty-three thousand, one hundred thirty".

Divisors: 1 2 5 10 1121443313 2242886626 5607216565 11214433130