Base | Representation |
---|---|
bin | 11001011111111010101101… |
… | …111001001010110000111110 |
3 | 112201001220120222010021011010 |
4 | 121133322231321022300332 |
5 | 104144333430431340410 |
6 | 1034302251151340050 |
7 | 32423113406052240 |
oct | 3137725571126076 |
9 | 481056528107133 |
10 | 112144513543230 |
11 | 32807248325a33 |
12 | 106b2436821626 |
13 | 4a7624a53384c |
14 | 1d99b75652090 |
15 | ce72097c7c20 |
hex | 65feade4ac3e |
112144513543230 has 64 divisors (see below), whose sum is σ = 307631744985600. Its totient is φ = 25630084585344.
The previous prime is 112144513543211. The next prime is 112144513543261. The reversal of 112144513543230 is 32345315441211.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28867629 + ... + 32521208.
It is an arithmetic number, because the mean of its divisors is an integer number (4806746015400).
Almost surely, 2112144513543230 is an apocalyptic number.
112144513543230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
112144513543230 is an abundant number, since it is smaller than the sum of its proper divisors (195487231442370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112144513543230 is a wasteful number, since it uses less digits than its factorization.
112144513543230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61397553.
The product of its (nonzero) digits is 172800, while the sum is 39.
Adding to 112144513543230 its reverse (32345315441211), we get a palindrome (144489828984441).
The spelling of 112144513543230 in words is "one hundred twelve trillion, one hundred forty-four billion, five hundred thirteen million, five hundred forty-three thousand, two hundred thirty".
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