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112145240003 = 241441464483
BaseRepresentation
bin110100001110001100…
…0001000111111000011
3101201110121001110102112
41220130120020333003
53314133140140003
6123304021405535
711050030545326
oct1503430107703
9351417043375
10112145240003
1143619078735
12198992698ab
13a762a976a4
1455dc0887bd
152db55e93d8
hex1a1c608fc3

112145240003 has 4 divisors (see below), whose sum is σ = 112145945928. Its totient is φ = 112144534080.

The previous prime is 112145239993. The next prime is 112145240029. The reversal of 112145240003 is 300042541211.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 112145240003 - 216 = 112145174467 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112145240903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9200 + ... + 473682.

It is an arithmetic number, because the mean of its divisors is an integer number (28036486482).

Almost surely, 2112145240003 is an apocalyptic number.

112145240003 is a deficient number, since it is larger than the sum of its proper divisors (705925).

112145240003 is an equidigital number, since it uses as much as digits as its factorization.

112145240003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705924.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 112145240003 its reverse (300042541211), we get a palindrome (412187781214).

The spelling of 112145240003 in words is "one hundred twelve billion, one hundred forty-five million, two hundred forty thousand, three".

Divisors: 1 241441 464483 112145240003