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112146201463 = 160336994711
BaseRepresentation
bin110100001110001101…
…1110011101101110111
3101201110122212022022011
41220130123303231313
53314133411421323
6123304054145051
711050041661402
oct1503433635567
9351418768264
10112146201463
114361967502a
1219899652187
13a7630431ba
1455dc258d39
152db573920d
hex1a1c6f3b77

112146201463 has 4 divisors (see below), whose sum is σ = 112153212208. Its totient is φ = 112139190720.

The previous prime is 112146201451. The next prime is 112146201467. The reversal of 112146201463 is 364102641211.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 112146201463 - 233 = 103556266871 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112146201467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3481323 + ... + 3513388.

It is an arithmetic number, because the mean of its divisors is an integer number (28038303052).

Almost surely, 2112146201463 is an apocalyptic number.

112146201463 is a deficient number, since it is larger than the sum of its proper divisors (7010745).

112146201463 is an equidigital number, since it uses as much as digits as its factorization.

112146201463 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7010744.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 112146201463 its reverse (364102641211), we get a palindrome (476248842674).

The spelling of 112146201463 in words is "one hundred twelve billion, one hundred forty-six million, two hundred one thousand, four hundred sixty-three".

Divisors: 1 16033 6994711 112146201463