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112146565757 is a prime number
BaseRepresentation
bin110100001110001110…
…1001100101001111101
3101201110200112211000112
41220130131030221331
53314134010101012
6123304110035405
711050045036442
oct1503435145175
9351420484015
10112146565757
11436198a37a6
12198997a8b65
13a76313cc65
1455dc3119c9
152db57ac122
hex1a1c74ca7d

112146565757 has 2 divisors, whose sum is σ = 112146565758. Its totient is φ = 112146565756.

The previous prime is 112146565723. The next prime is 112146565759. The reversal of 112146565757 is 757565641211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97337136121 + 14809429636 = 311989^2 + 121694^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112146565757 is a prime.

It is a super-2 number, since 2×1121465657572 (a number of 23 digits) contains 22 as substring.

Together with 112146565759, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112146565759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56073282878 + 56073282879.

It is an arithmetic number, because the mean of its divisors is an integer number (56073282879).

Almost surely, 2112146565757 is an apocalyptic number.

It is an amenable number.

112146565757 is a deficient number, since it is larger than the sum of its proper divisors (1).

112146565757 is an equidigital number, since it uses as much as digits as its factorization.

112146565757 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1764000, while the sum is 50.

The spelling of 112146565757 in words is "one hundred twelve billion, one hundred forty-six million, five hundred sixty-five thousand, seven hundred fifty-seven".