Base | Representation |
---|---|
bin | 1010001100110011111010… |
… | …1011100010101000101111 |
3 | 1110201011102100111221221112 |
4 | 2203030332223202220233 |
5 | 2432222223032230221 |
6 | 35504110310422235 |
7 | 2235162250250222 |
oct | 243147653425057 |
9 | 43634370457845 |
10 | 11215211211311 |
11 | 3634387392328 |
12 | 13116bb66197b |
13 | 634788c70583 |
14 | 2aab6793b5b9 |
15 | 146b0026415b |
hex | a333eae2a2f |
11215211211311 has 2 divisors, whose sum is σ = 11215211211312. Its totient is φ = 11215211211310.
The previous prime is 11215211211221. The next prime is 11215211211431. The reversal of 11215211211311 is 11311211251211.
It is a m-pointer prime, because the next prime (11215211211431) can be obtained adding 11215211211311 to its product of digits (120).
It is a weak prime.
It is an emirp because it is prime and its reverse (11311211251211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11215211211311 - 218 = 11215210949167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11215211211511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5607605605655 + 5607605605656.
It is an arithmetic number, because the mean of its divisors is an integer number (5607605605656).
Almost surely, 211215211211311 is an apocalyptic number.
11215211211311 is a deficient number, since it is larger than the sum of its proper divisors (1).
11215211211311 is an equidigital number, since it uses as much as digits as its factorization.
11215211211311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120, while the sum is 23.
Adding to 11215211211311 its reverse (11311211251211), we get a palindrome (22526422462522).
The spelling of 11215211211311 in words is "eleven trillion, two hundred fifteen billion, two hundred eleven million, two hundred eleven thousand, three hundred eleven".
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