11216410020133 has 4 divisors (see below), whose sum is σ = 11216583132300. Its totient is φ = 11216236907968.

The previous prime is 11216410019959. The next prime is 11216410020187. The reversal of 11216410020133 is 33102001461211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1503071096004 + 9713338924129 = 1225998^2 + 3116623^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11216410020133 is a prime.

It is a super-3 number, since 3×11216410020133³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11216410020098 and 11216410020107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11216410020433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86458858 + ... + 86588491.

It is an arithmetic number, because the mean of its divisors is an integer number (2804145783075).

Almost surely, 2^{11216410020133} is an apocalyptic number.

It is an amenable number.

11216410020133 is a deficient number, since it is larger than the sum of its proper divisors (173112167).

11216410020133 is an equidigital number, since it uses as much as digits as its factorization.

11216410020133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 173112166.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 11216410020133 its reverse (33102001461211), we get a palindrome (44318411481344).

The spelling of 11216410020133 in words is "eleven trillion, two hundred sixteen billion, four hundred ten million, twenty thousand, one hundred thirty-three".