Base | Representation |
---|---|
bin | 10100111001010100… |
… | …01110110010110111 |
3 | 1001221211010012020101 |
4 | 22130222032302313 |
5 | 140433333012220 |
6 | 5053102014531 |
7 | 544666362643 |
oct | 123452166267 |
9 | 31854105211 |
10 | 11218250935 |
11 | 4837456a71 |
12 | 2210b77447 |
13 | 109a201c08 |
14 | 785c83c23 |
15 | 459d0130a |
hex | 29ca8ecb7 |
11218250935 has 4 divisors (see below), whose sum is σ = 13461901128. Its totient is φ = 8974600744.
The previous prime is 11218250929. The next prime is 11218250963. The reversal of 11218250935 is 53905281211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53905281211 = 877 ⋅61465543.
It is a cyclic number.
It is not a de Polignac number, because 11218250935 - 25 = 11218250903 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11218250894 and 11218250903.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1121825089 + ... + 1121825098.
It is an arithmetic number, because the mean of its divisors is an integer number (3365475282).
Almost surely, 211218250935 is an apocalyptic number.
11218250935 is a deficient number, since it is larger than the sum of its proper divisors (2243650193).
11218250935 is an equidigital number, since it uses as much as digits as its factorization.
11218250935 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2243650192.
The product of its (nonzero) digits is 21600, while the sum is 37.
The spelling of 11218250935 in words is "eleven billion, two hundred eighteen million, two hundred fifty thousand, nine hundred thirty-five".
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