Base | Representation |
---|---|
bin | 1010001101000101111000… |
… | …0001011001010001101011 |
3 | 1110201121212022200110100122 |
4 | 2203101132001121101223 |
5 | 2432312111143014011 |
6 | 35510224520553455 |
7 | 2235422565266102 |
oct | 243213601312153 |
9 | 43647768613318 |
10 | 11220032001131 |
11 | 3636430617048 |
12 | 131262602288b |
13 | 635076943925 |
14 | 2ab0a3cad039 |
15 | 146cd35bb3db |
hex | a345e05946b |
11220032001131 has 4 divisors (see below), whose sum is σ = 11229780075264. Its totient is φ = 11210283927000.
The previous prime is 11220032001109. The next prime is 11220032001133. The reversal of 11220032001131 is 13110023002211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11220032001131 - 230 = 11218958259307 is a prime.
It is a super-2 number, since 2×112200320011312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11220032001133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4874035340 + ... + 4874037641.
It is an arithmetic number, because the mean of its divisors is an integer number (2807445018816).
Almost surely, 211220032001131 is an apocalyptic number.
11220032001131 is a deficient number, since it is larger than the sum of its proper divisors (9748074133).
11220032001131 is an equidigital number, since it uses as much as digits as its factorization.
11220032001131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9748074132.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 11220032001131 its reverse (13110023002211), we get a palindrome (24330055003342).
The spelling of 11220032001131 in words is "eleven trillion, two hundred twenty billion, thirty-two million, one thousand, one hundred thirty-one".
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