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112201132013120 = 265629955664159
BaseRepresentation
bin11001100000101111011100…
…100111011111011001000000
3112201021022201210202112122102
4121200233130213133121000
5104201300404243404440
61034344253301525532
732430156435106463
oct3140573447373100
9481238653675572
10112201132013120
1132829261a42407
12107013b81138a8
134a7b6a1533a37
141d9c7c6d852da
15ce8920220b15
hex660bdc9df640

112201132013120 has 56 divisors (see below), whose sum is σ = 267221366496000. Its totient is φ = 44873326986752.

The previous prime is 112201132013111. The next prime is 112201132013129. The reversal of 112201132013120 is 21310231102211.

It is an interprime number because it is at equal distance from previous prime (112201132013111) and next prime (112201132013129).

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 112201132013092 and 112201132013101.

It is not an unprimeable number, because it can be changed into a prime (112201132013129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25816400 + ... + 29847759.

It is an arithmetic number, because the mean of its divisors is an integer number (4771810116000).

Almost surely, 2112201132013120 is an apocalyptic number.

112201132013120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

112201132013120 is an abundant number, since it is smaller than the sum of its proper divisors (155020234482880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112201132013120 is an equidigital number, since it uses as much as digits as its factorization.

112201132013120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55670475 (or 55670465 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 112201132013120 its reverse (21310231102211), we get a palindrome (133511363115331).

The spelling of 112201132013120 in words is "one hundred twelve trillion, two hundred one billion, one hundred thirty-two million, thirteen thousand, one hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 32 40 64 80 160 320 6299 12598 25196 31495 50392 62990 100784 125980 201568 251960 403136 503920 1007840 2015680 55664159 111328318 222656636 278320795 445313272 556641590 890626544 1113283180 1781253088 2226566360 3562506176 4453132720 8906265440 17812530880 350628537541 701257075082 1402514150164 1753142687705 2805028300328 3506285375410 5610056600656 7012570750820 11220113201312 14025141501640 22440226402624 28050283003280 56100566006560 112201132013120