Base | Representation |
---|---|
bin | 11001100000101111011100… |
… | …100111011111011001000000 |
3 | 112201021022201210202112122102 |
4 | 121200233130213133121000 |
5 | 104201300404243404440 |
6 | 1034344253301525532 |
7 | 32430156435106463 |
oct | 3140573447373100 |
9 | 481238653675572 |
10 | 112201132013120 |
11 | 32829261a42407 |
12 | 107013b81138a8 |
13 | 4a7b6a1533a37 |
14 | 1d9c7c6d852da |
15 | ce8920220b15 |
hex | 660bdc9df640 |
112201132013120 has 56 divisors (see below), whose sum is σ = 267221366496000. Its totient is φ = 44873326986752.
The previous prime is 112201132013111. The next prime is 112201132013129. The reversal of 112201132013120 is 21310231102211.
It is an interprime number because it is at equal distance from previous prime (112201132013111) and next prime (112201132013129).
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 112201132013092 and 112201132013101.
It is not an unprimeable number, because it can be changed into a prime (112201132013129) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25816400 + ... + 29847759.
It is an arithmetic number, because the mean of its divisors is an integer number (4771810116000).
Almost surely, 2112201132013120 is an apocalyptic number.
112201132013120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
112201132013120 is an abundant number, since it is smaller than the sum of its proper divisors (155020234482880).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112201132013120 is an equidigital number, since it uses as much as digits as its factorization.
112201132013120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55670475 (or 55670465 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 112201132013120 its reverse (21310231102211), we get a palindrome (133511363115331).
The spelling of 112201132013120 in words is "one hundred twelve trillion, two hundred one billion, one hundred thirty-two million, thirteen thousand, one hundred twenty".
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