Base | Representation |
---|---|
bin | 10000010100111101001… |
… | …000011111010110100111 |
3 | 10222021002221201022021222 |
4 | 100110331020133112213 |
5 | 121340340044200012 |
6 | 2215240101130555 |
7 | 144030335330141 |
oct | 20247510372647 |
9 | 3867087638258 |
10 | 1122012100007 |
11 | 3a292a641587 |
12 | 1615536b9a5b |
13 | 81a612a5916 |
14 | 3c43cab7c91 |
15 | 1e2bd1be972 |
hex | 1053d21f5a7 |
1122012100007 has 2 divisors, whose sum is σ = 1122012100008. Its totient is φ = 1122012100006.
The previous prime is 1122012099997. The next prime is 1122012100127. The reversal of 1122012100007 is 7000012102211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1122012100007 - 28 = 1122012099751 is a prime.
It is a super-2 number, since 2×11220121000072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122012103007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561006050003 + 561006050004.
It is an arithmetic number, because the mean of its divisors is an integer number (561006050004).
Almost surely, 21122012100007 is an apocalyptic number.
1122012100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122012100007 is an equidigital number, since it uses as much as digits as its factorization.
1122012100007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 1122012100007 its reverse (7000012102211), we get a palindrome (8122024202218).
The spelling of 1122012100007 in words is "one trillion, one hundred twenty-two billion, twelve million, one hundred thousand, seven".
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