Base | Representation |
---|---|
bin | 10100111001100010… |
… | …10111011000001111 |
3 | 1001221221122012121212 |
4 | 22130301113120033 |
5 | 140434322333403 |
6 | 5053210045035 |
7 | 545021312222 |
oct | 123461273017 |
9 | 31857565555 |
10 | 11220121103 |
11 | 4838514064 |
12 | 221171977b |
13 | 109a708219 |
14 | 78620d5b9 |
15 | 45a0704d8 |
hex | 29cc5760f |
11220121103 has 2 divisors, whose sum is σ = 11220121104. Its totient is φ = 11220121102.
The previous prime is 11220121051. The next prime is 11220121117. The reversal of 11220121103 is 30112102211.
It is an a-pointer prime, because the next prime (11220121117) can be obtained adding 11220121103 to its sum of digits (14).
It is a strong prime.
It is an emirp because it is prime and its reverse (30112102211) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11220121103 is a prime.
It is a super-2 number, since 2×112201211032 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220121123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610060551 + 5610060552.
It is an arithmetic number, because the mean of its divisors is an integer number (5610060552).
Almost surely, 211220121103 is an apocalyptic number.
11220121103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220121103 is an equidigital number, since it uses as much as digits as its factorization.
11220121103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11220121103 its reverse (30112102211), we get a palindrome (41332223314).
The spelling of 11220121103 in words is "eleven billion, two hundred twenty million, one hundred twenty-one thousand, one hundred three".
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