Base | Representation |
---|---|
bin | 1010001101000110001101… |
… | …0101010110110100010110 |
3 | 1110201122002112101011111022 |
4 | 2203101203111112310112 |
5 | 2432312302001320042 |
6 | 35510241423041142 |
7 | 2235425026631663 |
oct | 243214325266426 |
9 | 43648075334438 |
10 | 11220121120022 |
11 | 3636476956421 |
12 | 131264ba401b2 |
13 | 63508c2477b9 |
14 | 2ab0b1a6aa6a |
15 | 146cdb321cd2 |
hex | a3463556d16 |
11220121120022 has 4 divisors (see below), whose sum is σ = 16830181680036. Its totient is φ = 5610060560010.
The previous prime is 11220121120007. The next prime is 11220121120049. The reversal of 11220121120022 is 22002112102211.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×112201211200223 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805030280004 + ... + 2805030280007.
It is an arithmetic number, because the mean of its divisors is an integer number (4207545420009).
Almost surely, 211220121120022 is an apocalyptic number.
11220121120022 is a deficient number, since it is larger than the sum of its proper divisors (5610060560014).
11220121120022 is an equidigital number, since it uses as much as digits as its factorization.
11220121120022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5610060560013.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 11220121120022 its reverse (22002112102211), we get a palindrome (33222233222233).
The spelling of 11220121120022 in words is "eleven trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twenty thousand, twenty-two".
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