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11220121120022 = 25610060560011
BaseRepresentation
bin1010001101000110001101…
…0101010110110100010110
31110201122002112101011111022
42203101203111112310112
52432312302001320042
635510241423041142
72235425026631663
oct243214325266426
943648075334438
1011220121120022
113636476956421
12131264ba401b2
1363508c2477b9
142ab0b1a6aa6a
15146cdb321cd2
hexa3463556d16

11220121120022 has 4 divisors (see below), whose sum is σ = 16830181680036. Its totient is φ = 5610060560010.

The previous prime is 11220121120007. The next prime is 11220121120049. The reversal of 11220121120022 is 22002112102211.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×112201211200223 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805030280004 + ... + 2805030280007.

It is an arithmetic number, because the mean of its divisors is an integer number (4207545420009).

Almost surely, 211220121120022 is an apocalyptic number.

11220121120022 is a deficient number, since it is larger than the sum of its proper divisors (5610060560014).

11220121120022 is an equidigital number, since it uses as much as digits as its factorization.

11220121120022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5610060560013.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 11220121120022 its reverse (22002112102211), we get a palindrome (33222233222233).

The spelling of 11220121120022 in words is "eleven trillion, two hundred twenty billion, one hundred twenty-one million, one hundred twenty thousand, twenty-two".

Divisors: 1 2 5610060560011 11220121120022