Base | Representation |
---|---|
bin | 1010001101000110100000… |
… | …0110011101001101000111 |
3 | 1110201122022002212120112112 |
4 | 2203101220012131031013 |
5 | 2432312432440200403 |
6 | 35510253401211235 |
7 | 2235430020513032 |
oct | 243215006351507 |
9 | 43648262776475 |
10 | 11220201100103 |
11 | 3636508013666 |
12 | 1312672790b1b |
13 | 6350a299baa8 |
14 | 2ab0bc52a019 |
15 | 146ce336e9d8 |
hex | a346819d347 |
11220201100103 has 2 divisors, whose sum is σ = 11220201100104. Its totient is φ = 11220201100102.
The previous prime is 11220201100093. The next prime is 11220201100117. The reversal of 11220201100103 is 30100110202211.
It is an a-pointer prime, because the next prime (11220201100117) can be obtained adding 11220201100103 to its sum of digits (14).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11220201100103 - 224 = 11220184322887 is a prime.
It is a super-2 number, since 2×112202011001032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11220201100903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610100550051 + 5610100550052.
It is an arithmetic number, because the mean of its divisors is an integer number (5610100550052).
Almost surely, 211220201100103 is an apocalyptic number.
11220201100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11220201100103 is an equidigital number, since it uses as much as digits as its factorization.
11220201100103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11220201100103 its reverse (30100110202211), we get a palindrome (41320311302314).
The spelling of 11220201100103 in words is "eleven trillion, two hundred twenty billion, two hundred one million, one hundred thousand, one hundred three".
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