Base | Representation |
---|---|
bin | 10000010101000010011… |
… | …100110000110001001111 |
3 | 10222021100011120011002122 |
4 | 100111002130300301033 |
5 | 121341030413102203 |
6 | 2215253005043155 |
7 | 144032500452254 |
oct | 20250234606117 |
9 | 3867304504078 |
10 | 1122101300303 |
11 | 3a2975a27035 |
12 | 1615795564bb |
13 | 81a76907869 |
14 | 3c44a89742b |
15 | 1e2c5e3e538 |
hex | 10542730c4f |
1122101300303 has 2 divisors, whose sum is σ = 1122101300304. Its totient is φ = 1122101300302.
The previous prime is 1122101300261. The next prime is 1122101300377. The reversal of 1122101300303 is 3030031012211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1122101300303 - 230 = 1121027558479 is a prime.
It is a super-2 number, since 2×11221013003032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1122101300393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561050650151 + 561050650152.
It is an arithmetic number, because the mean of its divisors is an integer number (561050650152).
Almost surely, 21122101300303 is an apocalyptic number.
1122101300303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1122101300303 is an equidigital number, since it uses as much as digits as its factorization.
1122101300303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1122101300303 its reverse (3030031012211), we get a palindrome (4152132312514).
The spelling of 1122101300303 in words is "one trillion, one hundred twenty-two billion, one hundred one million, three hundred thousand, three hundred three".
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