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11221420213 is a prime number
BaseRepresentation
bin10100111001101100…
…10100100010110101
31001222001002012200001
422130312110202311
5140440140421323
65053253551301
7545035332553
oct123466244265
931861065601
1011221420213
114839221103
122212045531
13109aa71623
1478646abd3
1545a22a3ad
hex29cd948b5

11221420213 has 2 divisors, whose sum is σ = 11221420214. Its totient is φ = 11221420212.

The previous prime is 11221420201. The next prime is 11221420219. The reversal of 11221420213 is 31202412211.

11221420213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8867423889 + 2353996324 = 94167^2 + 48518^2 .

It is an emirp because it is prime and its reverse (31202412211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11221420213 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11221420219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5610710106 + 5610710107.

It is an arithmetic number, because the mean of its divisors is an integer number (5610710107).

Almost surely, 211221420213 is an apocalyptic number.

It is an amenable number.

11221420213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11221420213 is an equidigital number, since it uses as much as digits as its factorization.

11221420213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 11221420213 its reverse (31202412211), we get a palindrome (42423832424).

The spelling of 11221420213 in words is "eleven billion, two hundred twenty-one million, four hundred twenty thousand, two hundred thirteen".