Base | Representation |
---|---|
bin | 110100010000001111… |
… | …1010010001001011011 |
3 | 101201122101212002010012 |
4 | 1220200133102021123 |
5 | 3314303320041103 |
6 | 123314524112135 |
7 | 11051526100304 |
oct | 1504037221133 |
9 | 351571762105 |
10 | 112214221403 |
11 | 43654003459 |
12 | 198b839564b |
13 | a77416a69b |
14 | 56072c37ab |
15 | 2dbb6c32d8 |
hex | 1a207d225b |
112214221403 has 2 divisors, whose sum is σ = 112214221404. Its totient is φ = 112214221402.
The previous prime is 112214221373. The next prime is 112214221421. The reversal of 112214221403 is 304122412211.
It is a strong prime.
It is an emirp because it is prime and its reverse (304122412211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112214221403 - 222 = 112210027099 is a prime.
It is not a weakly prime, because it can be changed into another prime (112214223403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56107110701 + 56107110702.
It is an arithmetic number, because the mean of its divisors is an integer number (56107110702).
Almost surely, 2112214221403 is an apocalyptic number.
112214221403 is a deficient number, since it is larger than the sum of its proper divisors (1).
112214221403 is an equidigital number, since it uses as much as digits as its factorization.
112214221403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 112214221403 its reverse (304122412211), we get a palindrome (416336633614).
The spelling of 112214221403 in words is "one hundred twelve billion, two hundred fourteen million, two hundred twenty-one thousand, four hundred three".
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