Base | Representation |
---|---|
bin | 110100010000101111… |
… | …1010111011001100011 |
3 | 101201200120110112122022 |
4 | 1220201133113121203 |
5 | 3314322120121011 |
6 | 123320324132055 |
7 | 11052121634216 |
oct | 1504137273143 |
9 | 351616415568 |
10 | 112231020131 |
11 | 436625375aa |
12 | 19901b3702b |
13 | a77779c969 |
14 | 560961777d |
15 | 2dbcde08db |
hex | 1a217d7663 |
112231020131 has 2 divisors, whose sum is σ = 112231020132. Its totient is φ = 112231020130.
The previous prime is 112231020113. The next prime is 112231020137. The reversal of 112231020131 is 131020132211.
Together with previous prime (112231020113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112231020131 - 218 = 112230757987 is a prime.
It is a super-2 number, since 2×1122310201312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (112231020137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56115510065 + 56115510066.
It is an arithmetic number, because the mean of its divisors is an integer number (56115510066).
Almost surely, 2112231020131 is an apocalyptic number.
112231020131 is a deficient number, since it is larger than the sum of its proper divisors (1).
112231020131 is an equidigital number, since it uses as much as digits as its factorization.
112231020131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 112231020131 its reverse (131020132211), we get a palindrome (243251152342).
The spelling of 112231020131 in words is "one hundred twelve billion, two hundred thirty-one million, twenty thousand, one hundred thirty-one".
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