Base | Representation |
---|---|
bin | 10000010101010100010… |
… | …100011101100110100111 |
3 | 10222022010001201021220110 |
4 | 100111110110131212213 |
5 | 121342134141131120 |
6 | 2215342435104103 |
7 | 144043101026241 |
oct | 20252424354647 |
9 | 3868101637813 |
10 | 1122401114535 |
11 | 3a300a193998 |
12 | 161641a42033 |
13 | 81ac3a6bc2c |
14 | 3c47861d091 |
15 | 1e2e24132e0 |
hex | 1055451d9a7 |
1122401114535 has 16 divisors (see below), whose sum is σ = 1796494171104. Its totient is φ = 598396465152.
The previous prime is 1122401114399. The next prime is 1122401114539. The reversal of 1122401114535 is 5354111042211.
It is not a de Polignac number, because 1122401114535 - 231 = 1120253630887 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1122401114539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13548742 + ... + 13631331.
It is an arithmetic number, because the mean of its divisors is an integer number (112280885694).
Almost surely, 21122401114535 is an apocalyptic number.
1122401114535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1122401114535 is a deficient number, since it is larger than the sum of its proper divisors (674093056569).
1122401114535 is a wasteful number, since it uses less digits than its factorization.
1122401114535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27182834.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 1122401114535 its reverse (5354111042211), we get a palindrome (6476512156746).
The spelling of 1122401114535 in words is "one trillion, one hundred twenty-two billion, four hundred one million, one hundred fourteen thousand, five hundred thirty-five".
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