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112241306453 is a prime number
BaseRepresentation
bin110100010001000011…
…0100110101101010101
3101201201021211010211012
41220202012212231111
53314332233301303
6123321332422005
711052305235413
oct1504206465525
9351637733735
10112241306453
11436683228a1
1219905477905
13a779961943
14560ab342b3
152dbdc735d8
hex1a221a6b55

112241306453 has 2 divisors, whose sum is σ = 112241306454. Its totient is φ = 112241306452.

The previous prime is 112241306431. The next prime is 112241306461. The reversal of 112241306453 is 354603142211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101542920964 + 10698385489 = 318658^2 + 103433^2 .

It is a cyclic number.

It is not a de Polignac number, because 112241306453 - 222 = 112237112149 is a prime.

It is a super-2 number, since 2×1122413064532 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112241356453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56120653226 + 56120653227.

It is an arithmetic number, because the mean of its divisors is an integer number (56120653227).

Almost surely, 2112241306453 is an apocalyptic number.

It is an amenable number.

112241306453 is a deficient number, since it is larger than the sum of its proper divisors (1).

112241306453 is an equidigital number, since it uses as much as digits as its factorization.

112241306453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 112241306453 its reverse (354603142211), we get a palindrome (466844448664).

The spelling of 112241306453 in words is "one hundred twelve billion, two hundred forty-one million, three hundred six thousand, four hundred fifty-three".