Base | Representation |
---|---|
bin | 10100111010000001… |
… | …11101111101100110 |
3 | 1001222020100000022201 |
4 | 22131000331331212 |
5 | 140441344230202 |
6 | 5053433445114 |
7 | 545101136053 |
oct | 123500757546 |
9 | 31866300281 |
10 | 11224211302 |
11 | 483a858097 |
12 | 2212b7079a |
13 | 109b50ab65 |
14 | 78699602a |
15 | 45a5cc387 |
hex | 29d03df66 |
11224211302 has 4 divisors (see below), whose sum is σ = 16836316956. Its totient is φ = 5612105650.
The previous prime is 11224211227. The next prime is 11224211303. The reversal of 11224211302 is 20311242211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 20311242211 = 13 ⋅1562403247.
It is a self number, because there is not a number n which added to its sum of digits gives 11224211302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11224211303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806052824 + ... + 2806052827.
It is an arithmetic number, because the mean of its divisors is an integer number (4209079239).
Almost surely, 211224211302 is an apocalyptic number.
11224211302 is a deficient number, since it is larger than the sum of its proper divisors (5612105654).
11224211302 is an equidigital number, since it uses as much as digits as its factorization.
11224211302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5612105653.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11224211302 its reverse (20311242211), we get a palindrome (31535453513).
The spelling of 11224211302 in words is "eleven billion, two hundred twenty-four million, two hundred eleven thousand, three hundred two".
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