Base | Representation |
---|---|
bin | 10000010101111000001… |
… | …101010010011000010101 |
3 | 10222100200000200002011221 |
4 | 100111320031102120111 |
5 | 121344402310311313 |
6 | 2215522304130341 |
7 | 144064031546311 |
oct | 20257015223025 |
9 | 3870600602157 |
10 | 1123003213333 |
11 | 3a3299045701 |
12 | 16178b6069b1 |
13 | 81b8b720c01 |
14 | 3c4d4590b41 |
15 | 1e32a1e7c8d |
hex | 10578352615 |
1123003213333 has 8 divisors (see below), whose sum is σ = 1190500042752. Its totient is φ = 1055666141376.
The previous prime is 1123003213291. The next prime is 1123003213369. The reversal of 1123003213333 is 3333123003211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1123003213333 - 213 = 1123003205141 is a prime.
It is a super-2 number, since 2×11230032133332 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1123003213298 and 1123003213307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1123003213133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39924885 + ... + 39953002.
It is an arithmetic number, because the mean of its divisors is an integer number (148812505344).
Almost surely, 21123003213333 is an apocalyptic number.
It is an amenable number.
1123003213333 is a deficient number, since it is larger than the sum of its proper divisors (67496829419).
1123003213333 is an equidigital number, since it uses as much as digits as its factorization.
1123003213333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79878731.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 1123003213333 its reverse (3333123003211), we get a palindrome (4456126216544).
It can be divided in two parts, 1123003 and 213333, that added together give a 4-th power (1336336 = 344).
The spelling of 1123003213333 in words is "one trillion, one hundred twenty-three billion, three million, two hundred thirteen thousand, three hundred thirty-three".
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