Base | Representation |
---|---|
bin | 110100010010110100… |
… | …0000100111000010001 |
3 | 101201212102001000222120 |
4 | 1220211220010320101 |
5 | 3314442401144213 |
6 | 123331243324453 |
7 | 11053623520146 |
oct | 1504550047021 |
9 | 351772030876 |
10 | 112300412433 |
11 | 43698723010 |
12 | 19921220729 |
13 | a788c879b1 |
14 | 561491c3cd |
15 | 2dc404b423 |
hex | 1a25a04e11 |
112300412433 has 8 divisors (see below), whose sum is σ = 163346054496. Its totient is φ = 68060856000.
The previous prime is 112300412381. The next prime is 112300412461. The reversal of 112300412433 is 334214003211.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 112300412433 - 29 = 112300411921 is a prime.
It is a super-2 number, since 2×1123004124332 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (112300412033) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1701521368 + ... + 1701521433.
It is an arithmetic number, because the mean of its divisors is an integer number (20418256812).
Almost surely, 2112300412433 is an apocalyptic number.
It is an amenable number.
112300412433 is a deficient number, since it is larger than the sum of its proper divisors (51045642063).
112300412433 is a wasteful number, since it uses less digits than its factorization.
112300412433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3403042815.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 112300412433 its reverse (334214003211), we get a palindrome (446514415644).
The spelling of 112300412433 in words is "one hundred twelve billion, three hundred million, four hundred twelve thousand, four hundred thirty-three".
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