Base | Representation |
---|---|
bin | 10100111010101111… |
… | …00010111101010101 |
3 | 1001222122110201020221 |
4 | 22131113202331111 |
5 | 140444403130010 |
6 | 5054204354341 |
7 | 545202346543 |
oct | 123527427525 |
9 | 31878421227 |
10 | 11230130005 |
11 | 484312a986 |
12 | 2214b459b1 |
13 | 109c800b53 |
14 | 787696d93 |
15 | 45ad9adda |
hex | 29d5e2f55 |
11230130005 has 4 divisors (see below), whose sum is σ = 13476156012. Its totient is φ = 8984104000.
The previous prime is 11230129991. The next prime is 11230130017. The reversal of 11230130005 is 50003103211.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7383277476 + 3846852529 = 85926^2 + 62023^2 .
It is not a de Polignac number, because 11230130005 - 221 = 11228032853 is a prime.
It is a super-2 number, since 2×112301300052 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1123012996 + ... + 1123013005.
It is an arithmetic number, because the mean of its divisors is an integer number (3369039003).
Almost surely, 211230130005 is an apocalyptic number.
It is an amenable number.
11230130005 is a deficient number, since it is larger than the sum of its proper divisors (2246026007).
11230130005 is an equidigital number, since it uses as much as digits as its factorization.
11230130005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2246026006.
The product of its (nonzero) digits is 90, while the sum is 16.
Adding to 11230130005 its reverse (50003103211), we get a palindrome (61233233216).
The spelling of 11230130005 in words is "eleven billion, two hundred thirty million, one hundred thirty thousand, five".
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