Base | Representation |
---|---|
bin | 1010001101101011100000… |
… | …1101011001000101100011 |
3 | 1110202120221102022111200022 |
4 | 2203122320031121011203 |
5 | 2432443304031430430 |
6 | 35515015223544055 |
7 | 2236231133520101 |
oct | 243327015310543 |
9 | 43676842274608 |
10 | 11230135030115 |
11 | 363a745501281 |
12 | 13145855bb02b |
13 | 635cc6a954a1 |
14 | 2ab7819b0c71 |
15 | 1471c552b4e5 |
hex | a36b8359163 |
11230135030115 has 4 divisors (see below), whose sum is σ = 13476162036144. Its totient is φ = 8984108024088.
The previous prime is 11230135030087. The next prime is 11230135030237. The reversal of 11230135030115 is 51103053103211.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11230135030115 - 214 = 11230135013731 is a prime.
It is a super-2 number, since 2×112301350301152 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1123013503007 + ... + 1123013503016.
It is an arithmetic number, because the mean of its divisors is an integer number (3369040509036).
Almost surely, 211230135030115 is an apocalyptic number.
11230135030115 is a deficient number, since it is larger than the sum of its proper divisors (2246027006029).
11230135030115 is an equidigital number, since it uses as much as digits as its factorization.
11230135030115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2246027006028.
The product of its (nonzero) digits is 1350, while the sum is 26.
Adding to 11230135030115 its reverse (51103053103211), we get a palindrome (62333188133326).
The spelling of 11230135030115 in words is "eleven trillion, two hundred thirty billion, one hundred thirty-five million, thirty thousand, one hundred fifteen".
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