Base | Representation |
---|---|
bin | 1010001101101100111101… |
… | …1001100101001000001101 |
3 | 1110202121221112102100210000 |
4 | 2203123033121211020031 |
5 | 2433000103132214013 |
6 | 35515122003034513 |
7 | 2236243566542661 |
oct | 243331731451015 |
9 | 43677845370700 |
10 | 11230524101133 |
11 | 363a925092077 |
12 | 131467396ba39 |
13 | 63605957b41c |
14 | 2ab7bb52c8a1 |
15 | 1471e9781973 |
hex | a36cf66520d |
11230524101133 has 40 divisors (see below), whose sum is σ = 17979005138688. Its totient is φ = 6967939705056.
The previous prime is 11230524101129. The next prime is 11230524101143. The reversal of 11230524101133 is 33110142503211.
11230524101133 is a `hidden beast` number, since 1 + 1 + 2 + 3 + 0 + 524 + 1 + 0 + 1 + 133 = 666.
11230524101133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11230524101133 - 22 = 11230524101129 is a prime.
It is a super-2 number, since 2×112305241011332 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11230524101097 and 11230524101106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11230524101113) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 81393141 + ... + 81531002.
Almost surely, 211230524101133 is an apocalyptic number.
It is an amenable number.
11230524101133 is a deficient number, since it is larger than the sum of its proper divisors (6748481037555).
11230524101133 is a wasteful number, since it uses less digits than its factorization.
11230524101133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162924215 (or 162924206 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 27.
Adding to 11230524101133 its reverse (33110142503211), we get a palindrome (44340666604344).
The spelling of 11230524101133 in words is "eleven trillion, two hundred thirty billion, five hundred twenty-four million, one hundred one thousand, one hundred thirty-three".
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