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11230524101133 = 342337162924143
BaseRepresentation
bin1010001101101100111101…
…1001100101001000001101
31110202121221112102100210000
42203123033121211020031
52433000103132214013
635515122003034513
72236243566542661
oct243331731451015
943677845370700
1011230524101133
11363a925092077
12131467396ba39
1363605957b41c
142ab7bb52c8a1
151471e9781973
hexa36cf66520d

11230524101133 has 40 divisors (see below), whose sum is σ = 17979005138688. Its totient is φ = 6967939705056.

The previous prime is 11230524101129. The next prime is 11230524101143. The reversal of 11230524101133 is 33110142503211.

11230524101133 is a `hidden beast` number, since 1 + 1 + 2 + 3 + 0 + 524 + 1 + 0 + 1 + 133 = 666.

11230524101133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11230524101133 - 22 = 11230524101129 is a prime.

It is a super-2 number, since 2×112305241011332 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11230524101097 and 11230524101106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11230524101113) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 81393141 + ... + 81531002.

Almost surely, 211230524101133 is an apocalyptic number.

It is an amenable number.

11230524101133 is a deficient number, since it is larger than the sum of its proper divisors (6748481037555).

11230524101133 is a wasteful number, since it uses less digits than its factorization.

11230524101133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 162924215 (or 162924206 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 27.

Adding to 11230524101133 its reverse (33110142503211), we get a palindrome (44340666604344).

The spelling of 11230524101133 in words is "eleven trillion, two hundred thirty billion, five hundred twenty-four million, one hundred one thousand, one hundred thirty-three".

Divisors: 1 3 9 23 27 37 69 81 111 207 333 621 851 999 1863 2553 2997 7659 22977 68931 162924143 488772429 1466317287 3747255289 4398951861 6028193291 11241765867 13196855583 18084579873 33725297601 54253739619 101175892803 138648445693 162761218857 303527678409 415945337079 488283656571 1247836011237 3743508033711 11230524101133