Base | Representation |
---|---|
bin | 10000010101111110101… |
… | …101000111011010010111 |
3 | 10222100221121210012122102 |
4 | 100111332231013122113 |
5 | 121400113212022221 |
6 | 2215541200352315 |
7 | 144066524234024 |
oct | 20257655073227 |
9 | 3870847705572 |
10 | 1123112220311 |
11 | 3a3344629214 |
12 | 16180001569b |
13 | 81ba8199293 |
14 | 3c504c4854b |
15 | 1e334a7b30b |
hex | 1057eb47697 |
1123112220311 has 2 divisors, whose sum is σ = 1123112220312. Its totient is φ = 1123112220310.
The previous prime is 1123112220301. The next prime is 1123112220361. The reversal of 1123112220311 is 1130222113211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123112220311 is a prime.
It is a super-2 number, since 2×11231122203112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123112220301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561556110155 + 561556110156.
It is an arithmetic number, because the mean of its divisors is an integer number (561556110156).
Almost surely, 21123112220311 is an apocalyptic number.
1123112220311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123112220311 is an equidigital number, since it uses as much as digits as its factorization.
1123112220311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 1123112220311 its reverse (1130222113211), we get a palindrome (2253334333522).
The spelling of 1123112220311 in words is "one trillion, one hundred twenty-three billion, one hundred twelve million, two hundred twenty thousand, three hundred eleven".
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