Base | Representation |
---|---|
bin | 11001100010010110000011… |
… | …010100011100111111000000 |
3 | 112201122212002210220112220220 |
4 | 121202112003110130333000 |
5 | 104210102022032000000 |
6 | 1034511033400303040 |
7 | 32441136534046116 |
oct | 3142260324347700 |
9 | 481585083815826 |
10 | 112311303000000 |
11 | 32870a57659495 |
12 | 1071a824171a80 |
13 | 4a88bab29a1c0 |
14 | 1da3c78b57ab6 |
15 | ceb71c3411a0 |
hex | 66258351cfc0 |
112311303000000 has 1568 divisors, whose sum is σ = 410499385540608. Its totient is φ = 26931916800000.
The previous prime is 112311302999957. The next prime is 112311303000007. The reversal of 112311303000000 is 303113211.
It is a super-2 number, since 2×1123113030000002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112311303000007) by changing a digit.
It is a polite number, since it can be written in 223 ways as a sum of consecutive naturals, for example, 293240999809 + ... + 293241000191.
Almost surely, 2112311303000000 is an apocalyptic number.
112311303000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112311303000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (205249692770304).
112311303000000 is an abundant number, since it is smaller than the sum of its proper divisors (298188082540608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112311303000000 is an equidigital number, since it uses as much as digits as its factorization.
112311303000000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 617 (or 582 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 112311303000000 its reverse (303113211), we get a palindrome (112311606113211).
The spelling of 112311303000000 in words is "one hundred twelve trillion, three hundred eleven billion, three hundred three million", and thus it is an aban number.
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