Base | Representation |
---|---|
bin | 10100111010111000… |
… | …00011110001001011 |
3 | 1001222201200210222111 |
4 | 22131130003301023 |
5 | 141000204003341 |
6 | 5054250003151 |
7 | 545215404454 |
oct | 123534036113 |
9 | 31881623874 |
10 | 11231312971 |
11 | 484386873a |
12 | 22154164b7 |
13 | 109cb26428 |
14 | 7878c412b |
15 | 45b031681 |
hex | 29d703c4b |
11231312971 has 2 divisors, whose sum is σ = 11231312972. Its totient is φ = 11231312970.
The previous prime is 11231312969. The next prime is 11231313031. The reversal of 11231312971 is 17921313211.
11231312971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (17921313211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11231312971 - 21 = 11231312969 is a prime.
It is a super-2 number, since 2×112313129712 (a number of 21 digits) contains 22 as substring.
Together with 11231312969, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11231312951) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5615656485 + 5615656486.
It is an arithmetic number, because the mean of its divisors is an integer number (5615656486).
Almost surely, 211231312971 is an apocalyptic number.
11231312971 is a deficient number, since it is larger than the sum of its proper divisors (1).
11231312971 is an equidigital number, since it uses as much as digits as its factorization.
11231312971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2268, while the sum is 31.
The spelling of 11231312971 in words is "eleven billion, two hundred thirty-one million, three hundred twelve thousand, nine hundred seventy-one".
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