11231313001 has 4 divisors (see below), whose sum is σ = 11373481600. Its totient is φ = 11089144404.

The previous prime is 11231312971. The next prime is 11231313031. The reversal of 11231313001 is 10031313211.

11231313001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10031313211 = 1049 ⋅9562739.

It is an interprime number because it is at equal distance from previous prime (11231312971) and next prime (11231313031).

It is a cyclic number.

It is not a de Polignac number, because 11231313001 - 2⁵ = 11231312969 is a prime.

It is a super-2 number, since 2×11231313001² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11231313031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71084181 + ... + 71084338.

It is an arithmetic number, because the mean of its divisors is an integer number (2843370400).

Almost surely, 2^11231313001 is an apocalyptic number.

It is an amenable number.

11231313001 is a deficient number, since it is larger than the sum of its proper divisors (142168599).

11231313001 is an equidigital number, since it uses as much as digits as its factorization.

11231313001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142168598.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11231313001 its reverse (10031313211), we get a palindrome (21262626212).

The spelling of 11231313001 in words is "eleven billion, two hundred thirty-one million, three hundred thirteen thousand, one".