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1123132319999 is a prime number
BaseRepresentation
bin10000010101111111111…
…001110010100011111111
310222101000000121101020022
4100111333321302203333
5121400133333214444
62215543155242355
7144100160126504
oct20257771624377
93871000541208
101123132319999
113a3354a07428
121618068a93bb
1381bac3b5ba1
143c50779b4ab
151e3366eb9ee
hex1057fe728ff

1123132319999 has 2 divisors, whose sum is σ = 1123132320000. Its totient is φ = 1123132319998.

The previous prime is 1123132319951. The next prime is 1123132320001. The reversal of 1123132319999 is 9999132313211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1123132319999 is a prime.

It is a super-2 number, since 2×11231323199992 (a number of 25 digits) contains 22 as substring.

Together with 1123132320001, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1123132319999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1123132319909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561566159999 + 561566160000.

It is an arithmetic number, because the mean of its divisors is an integer number (561566160000).

Almost surely, 21123132319999 is an apocalyptic number.

1123132319999 is a deficient number, since it is larger than the sum of its proper divisors (1).

1123132319999 is an equidigital number, since it uses as much as digits as its factorization.

1123132319999 is an evil number, because the sum of its binary digits is even.

The product of its digits is 708588, while the sum is 53.

The spelling of 1123132319999 in words is "one trillion, one hundred twenty-three billion, one hundred thirty-two million, three hundred nineteen thousand, nine hundred ninety-nine".