Base | Representation |
---|---|
bin | 110100010011001111… |
… | …1110110100111010111 |
3 | 101201220102112220002201 |
4 | 1220212133312213113 |
5 | 3320010122042241 |
6 | 123332524545331 |
7 | 11054162015632 |
oct | 1504637664727 |
9 | 351812486081 |
10 | 112315034071 |
11 | 436a59aa509 |
12 | 199260b2247 |
13 | a78c007056 |
14 | 5616846c19 |
15 | 2dc5488931 |
hex | 1a267f69d7 |
112315034071 has 2 divisors, whose sum is σ = 112315034072. Its totient is φ = 112315034070.
The previous prime is 112315033991. The next prime is 112315034093. The reversal of 112315034071 is 170430513211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112315034071 - 211 = 112315032023 is a prime.
It is a super-2 number, since 2×1123150340712 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112315034171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56157517035 + 56157517036.
It is an arithmetic number, because the mean of its divisors is an integer number (56157517036).
Almost surely, 2112315034071 is an apocalyptic number.
112315034071 is a deficient number, since it is larger than the sum of its proper divisors (1).
112315034071 is an equidigital number, since it uses as much as digits as its factorization.
112315034071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520, while the sum is 28.
Adding to 112315034071 its reverse (170430513211), we get a palindrome (282745547282).
The spelling of 112315034071 in words is "one hundred twelve billion, three hundred fifteen million, thirty-four thousand, seventy-one".
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