Base | Representation |
---|---|
bin | 10000010110000101011… |
… | …001001010011000101111 |
3 | 10222101020102221001120112 |
4 | 100112011121022120233 |
5 | 121400330423231002 |
6 | 2220000245410235 |
7 | 144102356061242 |
oct | 20260531123057 |
9 | 3871212831515 |
10 | 1123224430127 |
11 | 3a33a19aa0a8 |
12 | 16183170997b |
13 | 81bc54c6417 |
14 | 3c515ad7259 |
15 | 1e33e843852 |
hex | 1058564a62f |
1123224430127 has 2 divisors, whose sum is σ = 1123224430128. Its totient is φ = 1123224430126.
The previous prime is 1123224430099. The next prime is 1123224430177. The reversal of 1123224430127 is 7210344223211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123224430127 is a prime.
It is a super-2 number, since 2×11232244301272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1123224430093 and 1123224430102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123224430177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561612215063 + 561612215064.
It is an arithmetic number, because the mean of its divisors is an integer number (561612215064).
Almost surely, 21123224430127 is an apocalyptic number.
1123224430127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123224430127 is an equidigital number, since it uses as much as digits as its factorization.
1123224430127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 1123224430127 its reverse (7210344223211), we get a palindrome (8333568653338).
The spelling of 1123224430127 in words is "one trillion, one hundred twenty-three billion, two hundred twenty-four million, four hundred thirty thousand, one hundred twenty-seven".
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