Base | Representation |
---|---|
bin | 10000010110000110100… |
… | …101011011011111100111 |
3 | 10222101021211112210211121 |
4 | 100112012211123133213 |
5 | 121400401033020033 |
6 | 2220002242114411 |
7 | 144103021031023 |
oct | 20260645333747 |
9 | 3871254483747 |
10 | 1123244423143 |
11 | 3a3402215157 |
12 | 16183834ba07 |
13 | 81bc96a65cb |
14 | 3c51861d383 |
15 | 1e34149262d |
hex | 1058695b7e7 |
1123244423143 has 2 divisors, whose sum is σ = 1123244423144. Its totient is φ = 1123244423142.
The previous prime is 1123244423141. The next prime is 1123244423269. The reversal of 1123244423143 is 3413244423211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1123244423143 - 21 = 1123244423141 is a prime.
Together with 1123244423141, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1123244423099 and 1123244423108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1123244423141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561622211571 + 561622211572.
It is an arithmetic number, because the mean of its divisors is an integer number (561622211572).
Almost surely, 21123244423143 is an apocalyptic number.
1123244423143 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123244423143 is an equidigital number, since it uses as much as digits as its factorization.
1123244423143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 34.
Adding to 1123244423143 its reverse (3413244423211), we get a palindrome (4536488846354).
The spelling of 1123244423143 in words is "one trillion, one hundred twenty-three billion, two hundred forty-four million, four hundred twenty-three thousand, one hundred forty-three".
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