11234100000031 has 4 divisors (see below), whose sum is σ = 11418265573864. Its totient is φ = 11049934426200.

The previous prime is 11234100000029. The next prime is 11234100000061. The reversal of 11234100000031 is 13000000143211.

11234100000031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11234100000031 - 2¹ = 11234100000029 is a prime.

It is a super-2 number, since 2×11234100000031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11234099999960 and 11234100000014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11234100000061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92082786825 + ... + 92082786946.

It is an arithmetic number, because the mean of its divisors is an integer number (2854566393466).

Almost surely, 2^{11234100000031} is an apocalyptic number.

11234100000031 is a deficient number, since it is larger than the sum of its proper divisors (184165573833).

11234100000031 is an equidigital number, since it uses as much as digits as its factorization.

11234100000031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 184165573832.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11234100000031 its reverse (13000000143211), we get a palindrome (24234100143242).

It can be divided in two parts, 112 and 34100000031, that added together give a palindrome (34100000143).

The spelling of 11234100000031 in words is "eleven trillion, two hundred thirty-four billion, one hundred million, thirty-one", and thus it is an aban number.