Base | Representation |
---|---|
bin | 10000010110010000100… |
… | …100110110010100000101 |
3 | 10222101201111221210001221 |
4 | 100112100210312110011 |
5 | 121401221440334023 |
6 | 2220031030520341 |
7 | 144110124544501 |
oct | 20262044662405 |
9 | 3871644853057 |
10 | 1123412043013 |
11 | 3a34888a1477 |
12 | 1618845060b1 |
13 | 81c25334470 |
14 | 3c5329b3301 |
15 | 1e35105285d |
hex | 10590936505 |
1123412043013 has 32 divisors (see below), whose sum is σ = 1247572771200. Its totient is φ = 1004879437056.
The previous prime is 1123412043011. The next prime is 1123412043059. The reversal of 1123412043013 is 3103402143211.
It is a cyclic number.
It is not a de Polignac number, because 1123412043013 - 21 = 1123412043011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1123412043011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 129585243 + ... + 129593911.
It is an arithmetic number, because the mean of its divisors is an integer number (38986649100).
Almost surely, 21123412043013 is an apocalyptic number.
1123412043013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1123412043013 is a deficient number, since it is larger than the sum of its proper divisors (124160728187).
1123412043013 is a wasteful number, since it uses less digits than its factorization.
1123412043013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9781.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1123412043013 its reverse (3103402143211), we get a palindrome (4226814186224).
The spelling of 1123412043013 in words is "one trillion, one hundred twenty-three billion, four hundred twelve million, forty-three thousand, thirteen".
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