112341310000000 has 256 divisors, whose sum is σ = 284498588088000. Its totient is φ = 44174656000000.

The previous prime is 112341309999967. The next prime is 112341310000039. The reversal of 112341310000000 is 13143211.

It is a super-2 number, since 2×112341310000000² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 589904796 + ... + 590095204.

Almost surely, 2^{112341310000000} is an apocalyptic number.

112341310000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112341310000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (142249294044000).

112341310000000 is an abundant number, since it is smaller than the sum of its proper divisors (172157278088000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112341310000000 is an frugal number, since it uses more digits than its factorization.

112341310000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190517 (or 190475 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 112341310000000 its reverse (13143211), we get a palindrome (112341323143211).

The spelling of 112341310000000 in words is "one hundred twelve trillion, three hundred forty-one billion, three hundred ten million", and thus it is an aban number.