Base | Representation |
---|---|
bin | 10100111011001110… |
… | …01100100001010111 |
3 | 1001222221012010200202 |
4 | 22131213030201113 |
5 | 141001430414112 |
6 | 5054432331115 |
7 | 545252254106 |
oct | 123547144127 |
9 | 31887163622 |
10 | 11234232407 |
11 | 48454820a2 |
12 | 22163a3a9b |
13 | 10a06091c8 |
14 | 78804403d |
15 | 45b40b6c2 |
hex | 29d9cc857 |
11234232407 has 2 divisors, whose sum is σ = 11234232408. Its totient is φ = 11234232406.
The previous prime is 11234232389. The next prime is 11234232409. The reversal of 11234232407 is 70423243211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11234232407 - 26 = 11234232343 is a prime.
Together with 11234232409, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11234232407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234232409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617116203 + 5617116204.
It is an arithmetic number, because the mean of its divisors is an integer number (5617116204).
Almost surely, 211234232407 is an apocalyptic number.
11234232407 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234232407 is an equidigital number, since it uses as much as digits as its factorization.
11234232407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 29.
Adding to 11234232407 its reverse (70423243211), we get a palindrome (81657475618).
The spelling of 11234232407 in words is "eleven billion, two hundred thirty-four million, two hundred thirty-two thousand, four hundred seven".
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