Base | Representation |
---|---|
bin | 10100111011001111… |
… | …00000100001101101 |
3 | 1001222221100022002122 |
4 | 22131213200201231 |
5 | 141001441024344 |
6 | 5054434202325 |
7 | 545253045026 |
oct | 123547404155 |
9 | 31887308078 |
10 | 11234314349 |
11 | 4845528715 |
12 | 22164233a5 |
13 | 10a06375ab |
14 | 788065c4d |
15 | 45b425aee |
hex | 29d9e086d |
11234314349 has 2 divisors, whose sum is σ = 11234314350. Its totient is φ = 11234314348.
The previous prime is 11234314283. The next prime is 11234314387. The reversal of 11234314349 is 94341343211.
11234314349 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10672956100 + 561358249 = 103310^2 + 23693^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11234314349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234304349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617157174 + 5617157175.
It is an arithmetic number, because the mean of its divisors is an integer number (5617157175).
Almost surely, 211234314349 is an apocalyptic number.
It is an amenable number.
11234314349 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234314349 is an equidigital number, since it uses as much as digits as its factorization.
11234314349 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 35.
The spelling of 11234314349 in words is "eleven billion, two hundred thirty-four million, three hundred fourteen thousand, three hundred forty-nine".
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